In Perl (and many other compatible systems) use warnings (The - should be given first or last in a character class.) This extracts all words from hi,there-again!, without the punctuation. For example, to capture words separated by any of the listed punctuation + If your pattern need be more restrictive adjust the exclusion list. The defining property of the shown sample data is that the patterns of interest are separated by commas so I'd suggest to match anything-but-a-comma, using a negated character class +Īnd match (capture) globally - get all matches in the string. Then the trick is in writing the pattern so that it indeed matches all instances. What is needed is to instruct the regex to capture all matches, what is available in any regex implementation (language).
The problem with the attempted code, as discussed, is that there is one capture group matching repeatedly so in the end only the last match is kept. For instance in ruby I'd use something like str.split(",") or str.scan(/+/) IMHO, a regular expression is not one of them. That being said, I'd suggest not using regular expression in that case, there are many other great tools from a simple split to some tokenization patterns depending on your needs.
Since I'm not much of a swift guy, here's a ruby example: def make_regexp(group_regexp, count: 3, delimiter: ",")
You can see a fully detailed explanation about this regular expression on Regex101.Īs I said, it is pretty easy to generate this regexp for any groups you want using your favorite language. Will match the next sentences, with one, two or three capturing groups. For instance, if I want to match between 1 and 3 words, the regexp: ^(+)(?:,(+))?(?:,(+))?$ You can generate a regexp that will match either n words, as long as your n is predetermined. After reading Byte Commander's answer, I want to introduce a tiny possible improvement:
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